AB and CD are two parallel lines. PQ cuts AB and CD at E and F respect

1.	AB and CD are two parallel lines. PQ cuts AB and CD at E and F respectively. EL is the bisector of ∠FEB. If ∠LEB =35°, then ∠CFQ will beA. 55°B. 70°C. 110°D. 130°
Answer» Given that, AB ‖ CD and PQ cuts them EL is bisector of ∠FEB ∠LEB = ∠FEL = 35° ∠FEB = ∠LEB + ∠FEL = 35° + 35° = 70° ∠FEB = ∠EFC = 70°(Alternate angles) ∠EFC + ∠CFQ = 180°(Linear pair) 70° + ∠CFQ = 180° ∠CFQ = 110°

AB and CD are two parallel lines. PQ cuts AB and CD at E and F respectively. EL is the bisector of ∠FEB. If ∠LEB =35°, then ∠CFQ will beA. 55°B. 70°C. 110°D. 130°

Answer»

Given that,

AB ‖ CD and PQ cuts them

EL is bisector of ∠FEB

∠LEB = ∠FEL = 35°

∠FEB = ∠LEB + ∠FEL

= 35° + 35°

= 70°

∠FEB = ∠EFC = 70°(Alternate angles)

∠EFC + ∠CFQ = 180°(Linear pair)

70° + ∠CFQ = 180°

∠CFQ = 110°