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AB crystallizes in a body centered cubic lattice with edge length ‘a’ equal to 387 pm. The distance between two oppositely charged ions in the lattice is ...........(A) 335 pm(B) 250 pm(C) 200 pm(D) 300 pm |
Answer» Correct answer is: (A) 335 pm Distance between two oppositely charged ions (r+ + r- ) = \(\cfrac{\sqrt{3}a}{2}\) = 387 \(\times\)\(\cfrac{\sqrt{3}}{2}\) = 335.14 pm |
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