InterviewSolution
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InterviewSolution
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AB is `1` meter long uniform wire of `10 Omega` resistance. Other data are shown in the diagram. Calculate (i) potential gradient along `AB` (ii) length `AO` when galvanometer shown deflection |
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Answer» Correct Answer - (i)`0.016 V cm^(-1)`(ii)`31.2 cm` (i) potential gradent along `AB` `= ((4)/(15v + 10)) (10)/(100) = 0.016 V cm^(-1)` (ii) current through `0.6 Omega = (1.5)/(1.2 xx 0.6) = (5)/(6) A` pot diff across `0.3 Omega =(3)/(6) xx 0.6 = 0.5 V` Across length `AO, V = 0.3 V `is to be balance Let `l` be the length `AO` then `0.5 = 0.016 xx l or I = (0.5)/(0.016) = 31.2 cm` |
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