1.

AB is a line-segment. P and Q are points on opposite sides of AB such that each of them is equidistant from the points A and B (see Fig. 7.37). Show that the line PQ is the perpendicular bisector of AB

Answer» In`/_APQ and /_BPQ`
PA=PB
QA=QB
PQ=PQ
`/_APQcong/_BPQ`(SSS)
`angleAPQ=angleBPQ`
`angleAQP=angleBQP`
`anglePAQ=anglePBQ`
In `/_APC and /_BPC`
`angleAPC=angleBPL`
`anglePAC=anglePBC`
AP=BP
`/_APC cong /_ BPC` (ASA)
`anglePCA=anglePCB`
AC=BC(C is Mid point of AB)
`anglePCA+anglePCB=180^0`
`2anglePCA=180^0`
`anglePCA=90^0`


Discussion

No Comment Found

Related InterviewSolutions