Saved Bookmarks
| 1. |
AB is part of a circuit as shown that absorbs energy at a rate of 50W. E is an emf device that has no internal resistance. A. Potential difference across AB is 48V.B. Emf of the device is 48 V.C. Point B is connected to the positive terminal of E.D. Rate of conversion from electrical to chemical energy is 48 W in device E. |
|
Answer» Correct Answer - B::D b.,d. Resistance absorbs energy at the rate of 2 W. Potential difference across AB is VAB. I = 50W. `V_(AB) = 50V` Drop across resistor is `2V`, therefore emf of E is 48 V. As AB is absorbing energy at the rate of 50 W, 48W is being absorbed by E. Thus, E is on charging i.e., current is entering from positive terminal of E. |
|