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AB is the chord on the parabola `y^2=4ax` with its vertex at A. BC is drawn perpendicular to AB meeitng the axis at C. The projection of BC on the axis of the parabola is : |
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Answer» AB:`(2at-0)/(at^2-0)=2/t` BC:slope=`-1/2` `y-2at=-1/2(n-at^2)` `2y-4at=-tx+at^3` `tx+2y-4at-at^3=0` `C(4a-at^2,0)` `DC=at^2+4a-a` `DC=4a` Option 3 is correct. |
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