Saved Bookmarks
| 1. |
AB is the diameter of a circle, center O.C is a point on circumference such that angle COB=θ. The area of the minor segment cut off by AC is equal to twice the area of sector BOC. Prove that sinθ2cosθ2=π(12−θ120)sinθ2cosθ2=π(12−θ120) |
|
Answer» AB is the diameter of a circle, center O.C is a point on circumference such that angle COB=θ. The area of the minor segment cut off by AC is equal to twice the area of sector BOC. Prove that sinθ2cosθ2=π(12−θ120)sinθ2cosθ2=π(12−θ120) |
|