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AB is the diameter of a circle, center O.C is a point on circumference such that angle COB=θ. The area of the minor segment cut off by AC is equal to twice the area of sector BOC. Prove that sinθ2cosθ2=π(12−θ120)sinθ2cosθ2=π(12−θ120)

Answer» AB is the diameter of a circle, center O.C is a point on circumference such that angle COB=θ. The area of the minor segment cut off by AC is equal to twice the area of sector BOC. Prove that
sinθ2cosθ2=π(12θ120)sinθ2cosθ2=π(12θ120)


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