1.

AB is the diameter of a circle, centre O. C is a point on the circumference such that ∠COB=θ. The area of the minor segment cut off by AC is equal to twice the area of the sector BOC. Prove that sinθ2 cosθ2=π(12−θ120).

Answer»

AB is the diameter of a circle, centre O. C is a point on the circumference such that COB=θ. The area of the minor segment cut off by AC is equal to twice the area of the sector BOC. Prove that sinθ2 cosθ2=π(12θ120).



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