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abc is a 3 digited number then abc + bca + cab is not divisible by ……………. A) a + b + c B) 3 C) 37 D) 10 |
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Answer» Correct option is (D) 10 abc is a 3-digit number \(\therefore\) abc = 100a+10b+c Now abc+bca+cab = (100a+10b+c) + (100b+10c+a) + (100c+10a+b) = (100a+10a+a) + (100b+10b+b) + (100c+10c+c) = 111a + 111b + 111c = 111 (a+b+c) = 3 \(\times\) 37 (a+b+c) \(\therefore\) 3, 37 & (a+b+c) are factors of abc+bca+cab. Thus, abc+bca+cab is divisible by 3, 37 and a+b+c, but not divisible by 10. Correct option is D) 10 |
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