1.

ABC is a cyclic triangle and the bisectors of angle BAC, angle ABC and angle BCA meet the circle at P,Q and R respectively. Then the angle angle RQP is:

Answer»

`90^(@)-(ANGLEB)/(2)`
`90^(@)+(angleB)/(2)`
`90^(@)+(ANGLEC)/(2)`
`90^(@)+(angleB)/(2)`

ANSWER :`90-(angleB)/(2)`


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