1.

ABC is a right angled triangular plate of uniform thickness. The sides are such that AB gt BC as shown in figure. I_(1),I_(2) and I_(3) are moments of inertia about AB,BC andAC respectively. Then, which of the following relation is correct ?

Answer»

`I_(1)=I_(2)=I_(3)`
`I_(2) gt I_(1) gt I_(3)`
`I_(3) LT I_(2) lt I_(1)`
`I_(2) gt I_(1) gt I_(2)`

Solution :For a given body, mass is same, so it will DEPEND only on the distribution of mass about the axis
The mass is farthest from axis BC, so `I_(2)` is maximum. Mass is nearest to axis AC, so `I_(3)` is minimum.
Hence, the CORRECT sequence will be
`I_(2) gt I_(1) gt I_(3)`


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