1.

ABC is a right angles triangle, right angled at C. Two particles start from A and C. along AC and CB respectively with uniform velocities u and v. The shortest distance between them is (AC=L)

Answer»

`(Lv)/(sqrt(v^(2)+U^(2)))`
`(LU)/(sqrt(v^(2)+u^(2)))`
`(Lv)/(sqrt(v^(2)-u^(2)))`
`sqrt(Lu)/(sqrt(v^(2)-u^(2)))`

ANSWER :A


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