1.

∆ABC is a right triangle right-angled at A and AD ⊥ BC. Then, BDDC=(a) ABAC2(b) ABAC(c) ABAD2(d) ABAD

Answer» ∆ABC is a right triangle right-angled at A and AD ⊥ BC. Then, BDDC=

(a) ABAC2

(b) ABAC

(c) ABAD2

(d) ABAD


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