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∆ABC is a right triangle right-angled at A and AD ⊥ BC. Then, BDDC=(a) ABAC2(b) ABAC(c) ABAD2(d) ABAD |
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Answer» ∆ABC is a right triangle right-angled at A and AD ⊥ BC. Then, (a) (b) (c) (d) |
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