ABC is a triangle, D is a point on AB such that AD=14AB and E is a point on AC such that AE=14 AC. Prove that DE = 14BC

ABC is a triangle, D is a point on AB such that AD=14AB and E is a poi

1.	ABC is a triangle, D is a point on AB such that AD=14AB and E is a point on AC such that AE=14 AC. Prove that DE = 14BC
Answer» ABC is a triangle, D is a point on AB such that $A D = \frac{1}{4} A B$ and E is a point on AC such that $A E = \frac{1}{4}$ AC. Prove that DE = $\frac{1}{4} B C$