ABC is a triangle in which ∠A = 90°, AN ⊥ BC, BC = 12 cm and AC = – InterviewSolution

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1.

ABC is a triangle in which ∠A = 90°, AN ⊥ BC, BC = 12 cm and AC = 5 cm. Find the ratio of the areas of ΔANC and ΔABC.

Answer»

In Δ ANC and Δ ABC

∠C = ∠c (Common)

∠ANC = ∠BAC (Each 90°)

Then, Δ ANC ~ Δ ABC (By AA similarity)

By area of similarity triangle theorem.

Area of ΔABC/Area of ΔPQR = AC² /BC²

Or, 5²/12²

Or, 25/144

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