1.

ABC is a triangle with 1 as its incentre. The radii ofthe incircles of the triangles BIC, AIB and AIC are r_1,r_2" and "r_3 respectively. Prove that AI+BI+CI= (a(r-r_1))/(2r_1) + (b(r-r_2))/(2r_2)+(c(r-r_3))/(2r_3).

Answer»


ANSWER :`= (a(r-r_1))/(2r_1) + (B(r-r_2))/(2r_2)+(C(r-r_3))/(2r_3)`.


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