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ABC is an isosceles triangle in which AB = BC and D is a point on the side AB. If AD = BD, then CD is |
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Answer» Step-by-step explanation:We have, BC2=AC×CD and AB=AC⇒ BC×BC=AC×CD and ∠B=∠C⇒ ACBC=BCCD and ∠B=∠C⇒ CABC=CBDC and ∠B=∠CSo, by SAS-criterion of similarity, we have △BCA∼△DCB⇒ DCBC=CBCA=DBBA⇒ CBCA=DBBA⇒ CABA=CBDB⇒ 1=CBDB [∵ BA=CA]⇒ DB=CB⇒BD=BC [Hence PROVED]pls MARK it as BRAINLIEST |
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