ABC is an isosceles triangle in which AB = BC and D is a point on the side AB. If AD = BD, then CD is

ABC is an isosceles triangle in which AB = BC and D is a point on the

1.	ABC is an isosceles triangle in which AB = BC and D is a point on the side AB. If AD = BD, then CD is
Answer» <html><body><p>Step-by-step explanation:We have, BC2=AC×CD and AB=AC⇒ BC×BC=AC×CD and ∠B=∠C⇒ ACBC=BCCD and ∠B=∠C⇒ CABC=CBDC and ∠B=∠CSo, by SAS-criterion of similarity, we have △BCA∼△DCB⇒ DCBC=CBCA=DBBA⇒ CBCA=DBBA⇒ CABA=CBDB⇒ 1=CBDB [∵ BA=CA]⇒ DB=CB⇒BD=BC [Hence <a href="https://interviewquestions.tuteehub.com/tag/proved-7287273" style="font-weight:bold;" target="_blank" title="Click to know more about PROVED">PROVED</a>]pls <a href="https://interviewquestions.tuteehub.com/tag/mark-555248" style="font-weight:bold;" target="_blank" title="Click to know more about MARK">MARK</a> it as <a href="https://interviewquestions.tuteehub.com/tag/brainliest-1995348" style="font-weight:bold;" target="_blank" title="Click to know more about BRAINLIEST">BRAINLIEST</a></p></body></html>