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ABC is an isosceles triangle in which altitudes BE and CF are drawn to equal sides AC and AB respectively (see the given figure). Show that these altitudes are equal. |
Answer» In ΔAEB and ΔAFC, ∠AEB and ∠AFC (Each 90º) ∠A = ∠A (Common angle) AB = AC (Given) ∴ ΔAEB ≅ ΔAFC (By AAS congruence rule) ∴ BE = CF (By CPCT) |
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