1.

△ABC is constructed such that AB = 4 cm, BC = 5 cm and ∠A = 70∘. Taking side BC as base, another triangle BCD is constructed such that length of side BD is 3 cm and length of side CD is 3 cm. Then ∠DBC + ∠DCB equals

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ABC is constructed such that AB = 4 cm, BC = 5 cm and A = 70. Taking side BC as base, another triangle BCD is constructed such that length of side BD is 3 cm and length of side CD is 3 cm. Then DBC + DCB equals




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