1.

△ABC is constructed such that AB = 6 cm, BC = 4 cm and AC = 4 cm. Taking side AB as base, another triangle ABD is constructed such that the length of side BD is 3 cm and length of side AD is 5 cm, as shown below. Then ∠ACB + ∠ADB equals

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ABC is constructed such that AB = 6 cm, BC = 4 cm and AC = 4 cm. Taking side AB as base, another triangle ABD is constructed such that the length of side BD is 3 cm and length of side AD is 5 cm, as shown below. Then ACB + ADB equals




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