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ABC is isosceles triangle in which AB = AC = 7.6 cm and BC = 9.5 cm (attached fig.) The perpendicular AD from A on side BC is 4 cm. Find area of triangle ABC and measure of perpendicular B BE from B on side AC. |
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Answer» In ∆ABC, AB = AC = 7.6 cm Base BC = 9.5 cm Height o f triangle AD = 4 cm Area of ∆ABC = 1/2 x Base x Height = 1/2 x BC x AD = 1/2 x 9.5 x 4 = 9.5 x 2 = 19 sq. cm In isosceles triangle ABC AC = 7.6 cm and BE = ? Area of ∆ABC = 19 sq. cm ⇒ 1/2 x AC x BE = 19 ⇒ 1/2 x 7.6 x BE = 19 7.6 x BE = 19 x 2 ⇒ BE = 38/7.6 = 5 cm |
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