1.

ABC is isosceles triangle in which AB = AC = 7.6 cm and BC = 9.5 cm (attached fig.) The perpendicular AD from A on side BC is 4 cm. Find area of triangle ABC and measure of perpendicular B BE from B on side AC.

Answer»

In ∆ABC, AB = AC = 7.6 cm

Base BC = 9.5 cm

Height o f triangle AD = 4 cm

Area of ∆ABC = 1/2 x Base x Height

= 1/2 x BC x AD = 1/2 x 9.5 x 4

= 9.5 x 2 = 19 sq. cm

In isosceles triangle ABC

AC = 7.6 cm and BE = ?

Area of ∆ABC = 19 sq. cm

⇒ 1/2 x AC x BE = 19

⇒ 1/2 x 7.6 x BE = 19

7.6 x BE = 19 x 2

⇒ BE = 38/7.6 = 5 cm



Discussion

No Comment Found