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ABCD is a cyclic trapezium with AD || BC. If ∠B=70°, determine other three angles of the trapezium. |
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Answer» Given that, ABCD is a cyclic trapezium with AD ǁ BC and ∠B = 70° Since, ABCD is a quadrilateral Then, ∠B + ∠D = 180° 70° + ∠D = 180° ∠D = 110° Since, AD ǁ BC Then, ∠A + ∠B = 180° (Co. interior angle) ∠A + 70° = 180° ∠A = 110° Since, ABCD is a cyclic quadrilateral Then, ∠A + ∠C = 180° 110° + ∠C = 180° ∠C = 70° |
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