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ABCD is a parallelogram. The circle through A, B and C intersect CD (produced ifnecessary) at E. Prove that `A E = A D`. |
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Answer» ABCD is a parallelogram `/_ADC=/_ABC` Point E also lies on circle ABCE is a cyclic quadrilateral `/_AEC+/_ABC=180^0` `/_AEC=180-/_ADC` `/_AED=/_ADC` `/AED=/_ADE` In`/_ADE` `/_AED=/_ADE` AD=AE. |
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