1.

ABCD is a quadrilateral such that ∠ABC+∠ADC =180∘ inside the quadrilateral. Statement 1: the circumcircle of ΔABC intersects diagonal BD at D. Statement 2: the circumcircle of ΔABC intersects BD at D′inside the quadrilateral. Statement 3: the circumcircle of ΔABC intersects BD at D′ outside the quadrilateral. Statement 4: the circumcircle of ΔABC does not intersect BD at all. Statement 5: ABCD is called cyclic quadrilateral.

Answer»

ABCD is a quadrilateral such that ABC+ADC =180 inside the quadrilateral.

Statement 1: the circumcircle of ΔABC intersects diagonal BD at D.

Statement 2: the circumcircle of ΔABC intersects BD at Dinside the quadrilateral.

Statement 3: the circumcircle of ΔABC intersects BD at D outside the quadrilateral.

Statement 4: the circumcircle of ΔABC does not intersect BD at all.

Statement 5: ABCD is called cyclic quadrilateral.




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