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    				| 1. | ABCD is a rectangle with `A(-1,2),B(3,7)` and `AB:BC=4:3`. If P is the centre of the rectangle, then the distance of P from each corner is equal toA. `sqrt(14)/(2)`B. `3sqrt(41)/(4)`C. `2sqrt(41)/(3)`D. `5sqrt(41)/(8)` | 
| Answer» Correct Answer - D Since ABCD is a rectangle, `(AC)^2=(AB)^2+(BC)^2` `=(AB)^2[1+(9)/(16)]=(25)/(16)(AB)^2` and `PA=(AC)/(2)=(5AB)/(8)` `(5)/(8)sqrt((-1-3)^2+(2-7)^2)=5(sqrt41)/(8)` | |