InterviewSolution
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InterviewSolution
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ABCD is a square and EF || BD.R is mid point of EF. Prove that BE = DE |
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Answer» Since diagonal of a square bisects the vertex and BD is the diagonal of square ABCD.∴ ∠CBD =∠ CDB = 90/2 = 45°Given :EF || BD⇒∠ CEF =∠ CBD = 45° and∠ CEF =∠ CDB = 45° (Corresponding angles)⇒ CEF = CFE⇒ CE = CF (Sides opposite of equal angles are equal) .....(1)Now, BC = CD (Sides of square) .....(2)Subtracting (1) from(2), we get⇒ BC CE = CD CF⇒ BE = DF or DF = BE Hence, proved. |
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