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ABCD is a square. F is the midpoint of AB. BE is one -third of BC. If the area of ∆ FBE is 108 sq.cm, find the length of AC |
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Answer» We know that BF=AB/2 and BE=BC/3 Also given area of triangle FBE=108 area of triangle FBE=FB×BE/2 108=AB×BC/2×3×2 (where FB=AB/2 and BE=BC/3) AB×BC=1296 We know in square all sides are equal Therefore AB2 =1296 so AB=36 Now AC is a diagonal of the square so it's formula = side of square ×√2 Side of square is 36 Therefore AC=36 √2 Hope answer is what you want and if wrong please correct me
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