1.

ABCD is a square. F is the midpoint of AB. BE is one -third of BC. If the area of ∆ FBE is 108 sq.cm, find the length of AC

Answer»

We know that 

BF=AB/2 and BE=BC/3

Also given area of triangle FBE=108

area of triangle FBE=FB×BE/2

108=AB×BC/2×3×2 (where FB=AB/2 and BE=BC/3)

AB×BC=1296

We know in square all sides are equal 

Therefore AB=1296 so AB=36

Now AC is a diagonal of the square so it's formula = side of square ×√2

Side of square is 36

Therefore AC=36 √2 

Hope answer is what you want and if wrong please correct me

 



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