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ABCD is a square in which AC andBD are diagonals intersecting at OFind ZAOB. |
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Answer» Here is your answer: In ΔAOB and ΔCOB, AB = BC (we know that the sides of the square are equal) BO = BO (Common) OA = OC (The diagonals of square will bisect with each other) ΔAOB ≅ ΔCOB (SSS) ∠AOB = ∠COB [CPCT] ∠AOB + ∠COB = 180° (this is the linear pair) ∠AOB + ∠AOB = 180° ∠AOB = 90° |
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