1.

ABCD is a square in which AC andBD are diagonals intersecting at OFind ZAOB.

Answer»

Here is your answer:

In ΔAOB and ΔCOB,

AB = BC (we know that the sides of the square are equal)

BO = BO (Common)

OA = OC (The diagonals of square will bisect with each other)

ΔAOB ≅ ΔCOB (SSS)

∠AOB = ∠COB [CPCT]

∠AOB + ∠COB = 180° (this is the linear pair)

∠AOB + ∠AOB = 180°

∠AOB = 90°



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