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ABCD is a square whose side is a ; taking AB and AD as axes, prove that die equation of the circle circumscribing the square is x2+y2−a(x+y)=0. |
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Answer» ABCD is a square whose side is a ; taking AB and AD as axes, prove that die equation of the circle circumscribing the square is x2+y2−a(x+y)=0. |
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