1.

ABCD is a trapezium in which AB ∥ DC. If the area of the trapezium is 180 cm2 and length of AB is 17 cm, the height of the trapezium is 12 cm, then find the length of CD.1. 12 cm2. 13 cm3. 8 cm4. 10 cm

Answer» Correct Answer - Option 2 : 13 cm

Given:

ABCD is a trapezium, AB ∥ DC

The area of ABCD = 180 cm2

AB = 17 cm

Height of the trapezium = 12 cm

Formula Used:

Area of trapezium = 1/2 × height × (Sum of parallel sides)

Calculation:

Area of trapezium = 1/2 × height × (Sum of parallel sides)

⇒ 180 = 1/2 × 12 × (AB + CD)

⇒ 180 = 6 × (17 + CD)

⇒ CD = 30 – 17

⇒ CD = 13

∴ The length of CD is 13 cm.


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