ABCD is a trapezium in which AB ∥ DC. If the length of AB and CD is

1.	ABCD is a trapezium in which AB ∥ DC. If the length of AB and CD is 17 cm and 13 cm, the height of the trapezium is 12 cm, then find the area of trapezium.1. 120 cm22. 198 cm23. 180 cm24. 210 cm2
Answer» Correct Answer - Option 3 : 180 cm² Given: ABCD is a trapezium, AB ∥ DC AB = 17 cm CD = 13 cm Height of the trapezium = 12 cm Formula Used: Area of trapezium = 1/2 × height × (Sum of parallel sides) Calculation: Area of trapezium = 1/2 × height × (Sum of parallel sides) ⇒ 1/2 × 12 × (17 + 13) ⇒ 6 × 30 ⇒ 180 ∴ The area of trapezium is 180 cm².

ABCD is a trapezium in which AB ∥ DC. If the length of AB and CD is 17 cm and 13 cm, the height of the trapezium is 12 cm, then find the area of trapezium.1. 120 cm22. 198 cm23. 180 cm24. 210 cm2

Answer» Correct Answer - Option 3 : 180 cm²

Given:

ABCD is a trapezium, AB ∥ DC

AB = 17 cm

CD = 13 cm

Height of the trapezium = 12 cm

Formula Used:

Area of trapezium = 1/2 × height × (Sum of parallel sides)

Calculation:

Area of trapezium = 1/2 × height × (Sum of parallel sides)

⇒ 1/2 × 12 × (17 + 13)

⇒ 6 × 30

⇒ 180

∴ The area of trapezium is 180 cm².

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ABCD is a trapezium in which AB ∥ DC. If the length of AB and CD is 17 cm and 13 cm, the height of the trapezium is 12 cm, then find the area of trapezium.1. 120 cm22. 198 cm23. 180 cm24. 210 cm2

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