ABCD is a trapezium in which AB ∥ DC, M is mid-point of AD and N is

1.	ABCD is a trapezium in which AB ∥ DC, M is mid-point of AD and N is mid-point of BC. If the length of AB is 14 cm and the length of MN is 17 cm, then find the length of CD.1. 20 cm2. 10 cm3. 15 cm4. 25 cm
Answer» Correct Answer - Option 1 : 20 cm Given: ABCD is a trapezium, AB ∥ DC M is mid-point of AD N is mid-point of BC AB = 14 cm MN = 17 cm Formula Used: MN = 1/2 × (AB + CD) In a trapezium AB ∥ DC And M and N are mid-points of AD and BC respectively. Calculation: MN = 1/2 × (AB + CD) ⇒ 17 = 1/2 × (14 + CD) ⇒ 34 = 14 + CD ⇒ CD = 34 – 14 ⇒ CD = 20 cm ∴ The length of CD is 20 cm.

ABCD is a trapezium in which AB ∥ DC, M is mid-point of AD and N is mid-point of BC. If the length of AB is 14 cm and the length of MN is 17 cm, then find the length of CD.1. 20 cm2. 10 cm3. 15 cm4. 25 cm

Answer» Correct Answer - Option 1 : 20 cm

Given:

ABCD is a trapezium, AB ∥ DC

M is mid-point of AD

N is mid-point of BC

AB = 14 cm

MN = 17 cm

Formula Used:

MN = 1/2 × (AB + CD)

In a trapezium AB ∥ DC

And M and N are mid-points of AD and BC respectively.

Calculation:

MN = 1/2 × (AB + CD)

⇒ 17 = 1/2 × (14 + CD)

⇒ 34 = 14 + CD

⇒ CD = 34 – 14

⇒ CD = 20 cm

∴ The length of CD is 20 cm.

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ABCD is a trapezium in which AB ∥ DC, M is mid-point of AD and N is mid-point of BC. If the length of AB is 14 cm and the length of MN is 17 cm, then find the length of CD.1. 20 cm2. 10 cm3. 15 cm4. 25 cm

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