ABCD is a trapezium in which AB ∥ DC, M is mid-point of AD and N is

1.	ABCD is a trapezium in which AB ∥ DC, M is mid-point of AD and N is mid-point of BC. If the length of CD is 19 cm and the length of MN is 15.5 cm, then find the length of AB.1. 20 cm2. 12 cm3. 15 cm4. 18 cm
Answer» Correct Answer - Option 2 : 12 cm Given: ABCD is a trapezium, AB ∥ DC M is mid-point of AD N is mid-point of BC CD = 19 cm MN = 15.5 cm Formula Used: MN = 1/2 × (AB + CD) In a trapezium AB ∥ DC And M and N are mid-points of AD and BC respectively. Calculation: MN = 1/2 × (AB + CD) ⇒ 15.5 = 1/2 × (AB + 19) ⇒ 31 = AB + 19 ⇒ AB = 31 – 19 ⇒ AB = 12 cm ∴ The length of AB is 12 cm.

ABCD is a trapezium in which AB ∥ DC, M is mid-point of AD and N is mid-point of BC. If the length of CD is 19 cm and the length of MN is 15.5 cm, then find the length of AB.1. 20 cm2. 12 cm3. 15 cm4. 18 cm

Answer» Correct Answer - Option 2 : 12 cm

Given:

ABCD is a trapezium, AB ∥ DC

M is mid-point of AD

N is mid-point of BC

CD = 19 cm

MN = 15.5 cm

Formula Used:

MN = 1/2 × (AB + CD)

In a trapezium AB ∥ DC

And M and N are mid-points of AD and BC respectively.

Calculation:

MN = 1/2 × (AB + CD)

⇒ 15.5 = 1/2 × (AB + 19)

⇒ 31 = AB + 19

⇒ AB = 31 – 19

⇒ AB = 12 cm

∴ The length of AB is 12 cm.

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ABCD is a trapezium in which AB ∥ DC, M is mid-point of AD and N is mid-point of BC. If the length of CD is 19 cm and the length of MN is 15.5 cm, then find the length of AB.1. 20 cm2. 12 cm3. 15 cm4. 18 cm

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