ABCD is a trapezium in which AB ∥ DC, M is mid-point of AD and N is

1.	ABCD is a trapezium in which AB ∥ DC, M is mid-point of AD and N is mid-point of BC. If the length of AB is 18 cm and the length of CD is 12 cm, then find the length of MN.1. 20 cm2. 12 cm3. 15 cm4. 18 cm
Answer» Correct Answer - Option 3 : 15 cm Given: ABCD is a trapezium, AB ∥ DC M is mid-point of AD N is mid-point of BC AB = 18 cm CD = 12 cm Formula Used: MN = 1/2 × (AB + CD) In a trapezium AB ∥ DC And M and N are mid-points of AD and BC respectively. Calculation: MN = 1/2 × (AB + CD) ⇒ MN = 1/2 × (18 + 12) ⇒ MN = 1/2 × 30 ⇒ MN = 15 ∴ The length of MN is 15 cm.

ABCD is a trapezium in which AB ∥ DC, M is mid-point of AD and N is mid-point of BC. If the length of AB is 18 cm and the length of CD is 12 cm, then find the length of MN.1. 20 cm2. 12 cm3. 15 cm4. 18 cm

Answer» Correct Answer - Option 3 : 15 cm

Given:

ABCD is a trapezium, AB ∥ DC

M is mid-point of AD

N is mid-point of BC

AB = 18 cm

CD = 12 cm

Formula Used:

MN = 1/2 × (AB + CD)

In a trapezium AB ∥ DC

And M and N are mid-points of AD and BC respectively.

Calculation:

MN = 1/2 × (AB + CD)

⇒ MN = 1/2 × (18 + 12)

⇒ MN = 1/2 × 30

⇒ MN = 15

∴ The length of MN is 15 cm.

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ABCD is a trapezium in which AB ∥ DC, M is mid-point of AD and N is mid-point of BC. If the length of AB is 18 cm and the length of CD is 12 cm, then find the length of MN.1. 20 cm2. 12 cm3. 15 cm4. 18 cm

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