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ABCD is a trapezium in which AB ∥ DC, M is mid-point of AD and N is mid-point of BC. If the length of AB is 40.25 cm and the length of MN is 49 cm, then find the length of CD.1. 52.25 cm2. 48.75 cm3. 57.75 cm4. 59.50 cm |
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Answer» Correct Answer - Option 3 : 57.75 cm Given: ABCD is a trapezium, AB ∥ DC M is mid-point of AD N is mid-point of BC AB = 40.25 cm MN = 49 cm Formula Used: MN = 1/2 × (AB + CD) In a trapezium AB ∥ DC And M and N are mid-points of AD and BC respectively. Calculation: MN = 1/2 × (AB + CD) ⇒ 49 = 1/2 × (40.25 + CD) ⇒ 98 = 40.25 + CD ⇒ CD = 98 – 40.25 ⇒ CD = 57.75 cm ∴ The length of CD is 57.75 cm. |
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