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ABCDEF is a regular hexagon with centre at the origin such that AD + EB + FC = lambda ED. Then, lambda is equal to |
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Answer» 2 `implies (AE+ED)+(ED+DB)+2ED=lambdaED` `implies 4ED+(AE+DB)=lambdaED` `implies 4ED = lambda ED""[because AE=-DB]` `implies lambda = 4` Alternate Method Now, `AD+EB+FC=2(OD+EO+ED)` `=2(ED+ED)=4ED` `therefore lambda = 4` |
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