1.

ABCDEF is a regular hexagon with centre at the origin such that AD + EB + FC = lambda ED. Then, lambda is equal to

Answer»

2
4
6
3

Solution :Given, AD + EB + FC = `LAMBDA` ED

`implies (AE+ED)+(ED+DB)+2ED=lambdaED`
`implies 4ED+(AE+DB)=lambdaED`
`implies 4ED = lambda ED""[because AE=-DB]`
`implies lambda = 4`
Alternate Method
Now, `AD+EB+FC=2(OD+EO+ED)`
`=2(ED+ED)=4ED`
`therefore lambda = 4`


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