ABCDEF is a regular hexagon with point O as centre. Find the value of vec(AB)+vec(AC)+vec(AD)+vec(AE)+vec(AF).

ABCDEF is a regular hexagon with point O as centre. Find the value of

1.	ABCDEF is a regular hexagon with point O as centre. Find the value of vec(AB)+vec(AC)+vec(AD)+vec(AE)+vec(AF).
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :From the diagram <br/> `(vec(<a href="https://interviewquestions.tuteehub.com/tag/ab-360636" style="font-weight:bold;" target="_blank" title="Click to know more about AB">AB</a>)=-vec(DE))(vec(BC)=-vec(<a href="https://interviewquestions.tuteehub.com/tag/ef-445354" style="font-weight:bold;" target="_blank" title="Click to know more about EF">EF</a>))` <br/> `vec(AB)+vec(AC)+vec(<a href="https://interviewquestions.tuteehub.com/tag/ad-361679" style="font-weight:bold;" target="_blank" title="Click to know more about AD">AD</a>)+vec(AE)+vec(AF)` <br/> `=cancelvec(AB)+(cancelvec(AB)+cancelvec(BC))+vec(AD)+(cancelvec(AD)+cancelvec(DE))+(vec(AD)+cancelvec(DE)+cancelvec(EF))` <br/> `=3vec(AD)=3(2vec(AO))=6(vec(AO))`</body></html>