

InterviewSolution
Saved Bookmarks
1. |
ABCDEF is a regular hexagon with point O as centre. The value of `vec(AB)+vec(AC)+vec(AD)+vec(AE)+vec(AF)` is |
Answer» From the diagram `vec(AB)=vec(-DE),vec(BC)=vec(-EF)` `vec(AB)+vec(AC)+vec(AD)+vec(AE)+vec(AF)`. `=vec(AB)+(vec(AB)+vec(BC))+vec(AD)+(vec(AD)+vec(DE))+(vec(AD)+vec(DE)+vec(EF))` `=vec(3AD)=3(vec(2AO))=6vec((AO))` |
|