∆ABD is a right triangle right-angled at A and AC ⊥ BD. Show that(i) AB2 = BC . BD(ii) AC2 = BC . DC(iii) AD2 = BD . CD(iv) AB2AC2=BDDC

∆ABD is a right triangle right-angled at A and AC ⊥ BD. Show that(

1.	∆ABD is a right triangle right-angled at A and AC ⊥ BD. Show that(i) AB2 = BC . BD(ii) AC2 = BC . DC(iii) AD2 = BD . CD(iv) AB2AC2=BDDC
Answer» ∆ABD is a right triangle right-angled at A and AC ⊥ BD. Show that (i) AB² = BC . BD (ii) AC² = BC . DC (iii) AD² = BD . CD (iv) $\frac{{AB}^{2}}{{AC}^{2}} = \frac{BD}{DC}$

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∆ABD is a right triangle right-angled at A and AC ⊥ BD. Show that(i) AB2 = BC . BD(ii) AC2 = BC . DC(iii) AD2 = BD . CD(iv) AB2AC2=BDDC

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