Absorption of energy by an atom of hydrogen in the ground state results in the ejection of electron with de-Broglie wavelength λ=4.7×10−10 m. Given that the ionization energy is 13.6eV, calculate the energy of photon which caused the ejection of electron.

Absorption of energy by an atom of hydrogen in the ground state result

1.	Absorption of energy by an atom of hydrogen in the ground state results in the ejection of electron with de-Broglie wavelength λ=4.7×10−10 m. Given that the ionization energy is 13.6eV, calculate the energy of photon which caused the ejection of electron.
Answer» Absorption of energy by an atom of hydrogen in the ground state results in the ejection of electron with de-Broglie wavelength $λ = 4.7 \times 10^{- 10}$ m. Given that the ionization energy is 13.6eV, calculate the energy of photon which caused the ejection of electron.