Abullet of mss 20 g moving horizontally at speed of 300 m/s is fired into wooden block of mas 500 suspended by a long string. The bullet criosses the block and emerges on the other side. If the centre of mass of the block rises through a height of 20.0 cm, find teh speed of tbe bullet as it emerges from the block.

Abullet of mss 20 g moving horizontally at speed of 300 m/s is fired i

1.	Abullet of mss 20 g moving horizontally at speed of 300 m/s is fired into wooden block of mas 500 suspended by a long string. The bullet criosses the block and emerges on the other side. If the centre of mass of the block rises through a height of 20.0 cm, find teh speed of tbe bullet as it emerges from the block.
Answer» Mass of bullet `m=20 m =0.02kg ` Mass of wooden block `M=500 gm=0.5kg` Velocity of the bullet with which it strikes `u=300m/sec` Let tehh bullet emerges out with velociyt V and the velocity of block `v^1` As per law of conservation of momentum `mu=Mv^1+m_1v`.......i Again applying work energy principle for the block after the collision `0-(1/2)Mx(v^10^2=-M.g.h` (where h=0.2m) `rarr (v^2)^2=2gh` `=sqrt(20xx2.0)=2m/sec` Substituting the value `v^1` in equation i we get `0.02xx300=2+0.2xxv` `rarr v=(6-1)/0.02` `=5/0.02=250m/sec`

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