1.

AC. ProveIn AABC, D is any point in the interior of AABC such that DBC <DCB and ABthat AD bisects <BAC.CB and AB

Answer»

Given ∠DBC = ∠DCB .....(1)so, BD = DC .....(2)

Given : AB = ACSo, ∠ABC = ∠ACB ....(3)

Consider (3) - (1)So,∠ABD = ∠ACD .....(4)

In ∆ ABD and ∆ ADC,AB = AC∠ABD = ∠ACD from (4)BD = DC from (2)

By SAS rule ∆ ABD and ∆ ADC are congurent so ∠BAD = ∠CAD .So, AD bisect ∠ BAC

Thx



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