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AC. ProveIn AABC, D is any point in the interior of AABC such that DBC <DCB and ABthat AD bisects <BAC.CB and AB |
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Answer» Given ∠DBC = ∠DCB .....(1)so, BD = DC .....(2) Given : AB = ACSo, ∠ABC = ∠ACB ....(3) Consider (3) - (1)So,∠ABD = ∠ACD .....(4) In ∆ ABD and ∆ ADC,AB = AC∠ABD = ∠ACD from (4)BD = DC from (2) By SAS rule ∆ ABD and ∆ ADC are congurent so ∠BAD = ∠CAD .So, AD bisect ∠ BAC Thx |
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