Acceleration due to gravity is given by g = (GM / R2) what is the equ

1.	Acceleration due to gravity is given by g = (GM / R2) what is the equation of the fractional error Δg/g in measurement of gravity g ? [G & M constant](a) – (ΔR / R) (b) 2 (ΔR / R) (c) – 2(ΔR / R) (d) (1/2) (ΔR / R)
Answer» (b) 2 (ΔR / R) Explanation: g = [(GM) / R²] ∵ G & M are constant g is function of (1/R²) i.e. (1/R)² fractional error (Δg / g) = 2(ΔR / R)

Acceleration due to gravity is given by g = (GM / R2) what is the equation of the fractional error Δg/g in measurement of gravity g ? [G & M constant](a) – (ΔR / R) (b) 2 (ΔR / R) (c) – 2(ΔR / R) (d) (1/2) (ΔR / R)

Answer»

(b) 2 (ΔR / R)

Explanation:

g = [(GM) / R²]

∵ G & M are constant g is function of (1/R²) i.e. (1/R)² fractional error (Δg / g) = 2(ΔR / R)

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Acceleration due to gravity is given by g = (GM / R2) what is the equation of the fractional error Δg/g in measurement of gravity g ? [G &amp; M constant](a) – (ΔR / R) (b) 2 (ΔR / R) (c) – 2(ΔR / R) (d) (1/2) (ΔR / R)

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Acceleration due to gravity is given by g = (GM / R2) what is the equation of the fractional error Δg/g in measurement of gravity g ? [G & M constant](a) – (ΔR / R) (b) 2 (ΔR / R) (c) – 2(ΔR / R) (d) (1/2) (ΔR / R)