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Acceleration of particle moving in straight line can be written as `a=(dv)/(dt)=v(dv)/(dx)`. From the given graph find acceleration at `x=20 m`. |
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Answer» Correct Answer - `100 m//s^(2)` From graph `(dv)/(dx)=(90-50)/(40-20)=40/20(dv)/(dx)=2` `("at " x=20)=50 m//s` `a=v(dv)/(dx) rArr a=50xx2=100 m//s^(2)` |
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