Accidentally chewing on a stray fragmet of aluminium foil can causes a sharp tooth path if the aluminium comes in contact with an amalgam filing. The filing, an alloy of silver, tin and mercury, acts as the cathode of a tiny galvanic cell, the aluminium behaves as the anode, and salivas serves as the electrolyte. when the aluminium and the filling come in contact, and electric current passage from the aluminium to the filling which is sensed by a nerve in the tooth. Aluminium is oxidized at the anode, and `O_(2)` gas is reduced to water at the cathode. `E_(AI^(3+)//AI)^(@) =- 1.66 E_(O_(2)H^(+)//H_(2)O)6^(@) = 1.23 V` Standard `E.M.F` experienced by the person with dental filing is:A. 0.43VB. 2.89VC. 3.98VD. None of these

Accidentally chewing on a stray fragmet of aluminium foil can causes a

1.	Accidentally chewing on a stray fragmet of aluminium foil can causes a sharp tooth path if the aluminium comes in contact with an amalgam filing. The filing, an alloy of silver, tin and mercury, acts as the cathode of a tiny galvanic cell, the aluminium behaves as the anode, and salivas serves as the electrolyte. when the aluminium and the filling come in contact, and electric current passage from the aluminium to the filling which is sensed by a nerve in the tooth. Aluminium is oxidized at the anode, and `O_(2)` gas is reduced to water at the cathode. `E_(AI^(3+)//AI)^(@) =- 1.66 E_(O_(2)H^(+)//H_(2)O)6^(@) = 1.23 V` Standard `E.M.F` experienced by the person with dental filing is:A. 0.43VB. 2.89VC. 3.98VD. None of these
Answer» Correct Answer - B

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The EMF of the following cell: `Zn| Zn^(2+)(0.1M) || Cl^(-)(0.01M) | AgCl | Ag` is: [Given : E_(Zn^(2+)|/Zn)^(@) = -0.76V`, `E_(Cl^(-)| AgCl|Ag)^(@)` = 0.22 V`, `(2.303RT)/(F) = 0.06]`A. 0.96 VB. 0.345 VC. 1.23D. 1.13 V
`DeltaG^(@)` of the cell reaction `AgCl(s) + 1/2H_(2) rightarrow Ag(s) + H^(+) + Cl^(-)` is `-21.52kJ`. `DeltaG^(@)` of 2AgCl(s) + H_(2)(g) rightarrow + 2H^(+) + 2Cl^(-)` isA. `-21.52kJ`B. `-10.76 kJ`C. `-43.04kJ`D. `43.04 kJ`
The emf of the cell `Zn|ZnCl_(2)` (0.05M) | AgCl(s)`,Ag is 1.015 V at 298 K and the temperature coefficient of its emf is `-4.92 xx 10^(-4)` V/K. How many of the reaction thermodynamic parameter `DeltaG`, `DeltaS` and `DeltaH` are negative at 298 K?A. None of themB. One of themC. Two of themD. All of them
The Gibbs energy for the decomposition of `Al_(2)O_(3)` at `500^(@)C` is as follow : `(2)/(3)Al_(2)O_(3) rarr (4)/(3)Al+O_(2), Delta_(r)G= +960 kJ mol^(-1)` The potential difference needed for the electrolytic reduction of aluminium oxide `(Al_(2)O_(3))` at `500^(@)C` isA. 4.5 VB. 3.0 VC. 2.5 VD. 5.0 V
Based on the data given below, the correcy order of reducing power is: `Fe_((aq.))^(3+) + e rarr Fe_((aq.))^(2+), E^(@) = +0.77 V` `Al_((aq.))^(3+) + 3e rarr Al_((s)), E^(@) = -1.66 V` `Br_(2(aq.)) + 2e rarr 2Br_((aq.))^(-), E^(@) = +1.08 V`A. `Br^(-) lt Fe(2+) lt Al`B. `Fe^(2+) lt Al lt Br^(-)`C. `Al lt Br^(-) lt Fe^(2+)`D. `Al lt Fe^(2+) lt Br^(-)`
For the electrolytic production of `NaClO_(4)` from `NaClO_(3)` as per the following equation: `NaClO_(3) + H_(2)O rightarrow NaClO_(4) + H_(2)` How many faradays of electricity will be required to produce 0.5 "mole" of `NaClO_(4)` assuming 60% efficiency?A. 0.835 FB. 1.67 FC. 3.34 FD. 1.6 F
What must be concentration of `Ag^(+)` in an aqueous solution containing `Cu^(2+) =1.0 M` so that bot the metals can be deposited on the cathode simultaneously. Given that `E_(Cu//Cu^(2+))^(0)=-0.34V` and `E_(Ag^(+)//Ag)^(0)=0.812V,T=298K`A. Nearly `10^(-19)` MB. `10^(-12)` MC. `10^(-8)` MD. Nearly `10^(-16)` M
Which process occurs in the electrolysis of an aqueous tin (II) chloride solution at a tin anode?A. Sn = `Sn^(2+) + 2e^(-)`B. `2Cl^(-) = Cl_(2) + 2e^(-)`C. `2H_(2)O = O_(2) + 4H^(+) + 4e^(-)`D. None of these
How many electrons flow when a current of 5 amperes is passed through a conductor for 200 seconds?A. `6.241 xx 10^(21)`B. `6.0241 xx 10^(21)`C. `6.241 xx 10^(22)`D. `6.0241 xx 10^(20)`
The number of electrons delivered at the cathode during electrolysis by a current of `1` ampere in 60 seconds is (charger on electron `= 1.60 xx 10^(-19)C`)A. `3.74 xx 10^(20)`B. `6.0 xx 10^(23)`C. `7.48 xx 10^(21)`D. `6.0 xx 10^(20)`

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