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According to Stefan's law of radiation, a black body radiates energy sigmaT^(4) from its unit surface area every second where T is the surface temperature of the black body and sigma=5.67xx10^(-8)W//m^(2)K^(4) is known as Stefan's constant. A nuclear weapon may be thought of as a ball of radius 0.5 m. When detonated, it reaches temperature of 10^(6) K and can be treated as a black body. Estimate the power it radiates. |
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Answer» Solution :Power emitted according to STEFAN - Boltzmaan LAW, `P=sigmaAT^(4)` `=SIGMA(4piR^(2))T^(4)` `=5.67xx10^(-8)xx4xx3.14xx(0.5)^(2)xx(10^(6))^(4)` `=17.8xx10^(18)` `~~1.8xx10^(17)" J/s"` |
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