Acetamide and NaOBr//OH^(-) produce

1.	Acetamide and NaOBr//OH^(-) produce
Answer» <html><body><p>Ethanamine<<a href="https://interviewquestions.tuteehub.com/tag/br-390993" style="font-weight:bold;" target="_blank" title="Click to know more about BR">BR</a>>Methanamine<br/>`CH_(3)<a href="https://interviewquestions.tuteehub.com/tag/cn-907325" style="font-weight:bold;" target="_blank" title="Click to know more about CN">CN</a>`<br/>`NH_(3)`</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/hoffman-7754708" style="font-weight:bold;" target="_blank" title="Click to know more about HOFFMAN">HOFFMAN</a> Bromamide reaction <br/> `CH_(3) - <a href="https://interviewquestions.tuteehub.com/tag/overset-2905731" style="font-weight:bold;" target="_blank" title="Click to know more about OVERSET">OVERSET</a>(O)overset(\|\|)(C) - NH_(2) + Br_(2) + 4 <a href="https://interviewquestions.tuteehub.com/tag/naoh-572531" style="font-weight:bold;" target="_blank" title="Click to know more about NAOH">NAOH</a> rarr CH_(3) NH_(2) + Na_(2)CO_(3) + 2NaBr + H_(2)O`</body></html>

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