Acetamide and NaOBr//OH^(-) produce

1.	Acetamide and NaOBr//OH^(-) produce
Answer» Ethanamine<BR>Methanamine `CH_(3)CN` `NH_(3)` Solution :HOFFMAN Bromamide reaction `CH_(3) - OVERSET(O)overset(\|\|)(C) - NH_(2) + Br_(2) + 4 NAOH rarr CH_(3) NH_(2) + Na_(2)CO_(3) + 2NaBr + H_(2)O`

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