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Acetyl bromide reacts with excess of `CH_(3)Mgl` followed by treatment with a saturated solution of `NH_(4)Cl` givesA. 2-methyl-2-propanolB. AcetamideC. AcetoneD. Acetyl iodide |
Answer» Correct Answer - A `underset("Acetyl bromide ")(CH_(3)-overset(O)overset(|)C-Br)underset((ii)"Saturated " NH_(4)Cl)overset((i) "Excess"-CH_(3)MgI)to underset(2-"methyl" 2-"propanol")(CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-OH)` |
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