`Acl_(2)(excess)+BCl_(2) to Acl_(4)+Bdownarrow` `BO underset(gt400^(@)C)overset(Delta)to(1)/(2)O_(2)+B_(2)`. If A and B metal then ore of B would be:A. sideriteB. cinnabarC. malachiteD. horn silver

`Acl_(2)(excess)+BCl_(2) to Acl_(4)+Bdownarrow` `BO underset(gt400^(@)

1.	`Acl_(2)(excess)+BCl_(2) to Acl_(4)+Bdownarrow` `BO underset(gt400^(@)C)overset(Delta)to(1)/(2)O_(2)+B_(2)`. If A and B metal then ore of B would be:A. sideriteB. cinnabarC. malachiteD. horn silver
Answer» Correct Answer - B

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`Acl_(2)(excess)+BCl_(2) to Acl_(4)+Bdownarrow` `BO underset(gt400^(@)C)overset(Delta)to(1)/(2)O_(2)+B_(2)`. If A and B metal then ore of B would be:A. sideriteB. cinnabarC. malachiteD. horn silver

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