1.

Action and reaction forces are

Answer»

Unequal in magnitude and in same direction
Equal in magnitude and in same direction
Unequal in magnitude and in OPPOSITE direction
Equal in magnitude and opposite in direction

Solution :`F_(1)+F_(2)=16"______________(1)"`
Resultant force is PERPENDICULAR to `F_(1)`, then
`F_(2)^(2)-F_(1)^(2)=F^(2)`
`F_(2)^(2)-F_(1)^(2)=8^(2) RARR (F_(2)-F_(1))(F_(2)+F_(1))=64`
`(F_(2)-F_(1))xx16=64"_______________(2)"`
Solving (1) & (2), we get `F_(1)=6N, F_(2)=10N`


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