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Action and reaction forces are |
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Answer» Unequal in magnitude and in same direction Resultant force is PERPENDICULAR to `F_(1)`, then `F_(2)^(2)-F_(1)^(2)=F^(2)` `F_(2)^(2)-F_(1)^(2)=8^(2) RARR (F_(2)-F_(1))(F_(2)+F_(1))=64` `(F_(2)-F_(1))xx16=64"_______________(2)"` Solving (1) & (2), we get `F_(1)=6N, F_(2)=10N` |
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